Does the polynomial have a GCF that needs to be factored out using the Distributive
Law?
Do I recognize one of the three patterns of polynomials?
Difference of Squares factors to conjugate binomials. x2 - 25 = (x + 5)(x - 5)
Perfect Square Trinomial, all terms positive factors to Square of a Sum. x2 + 6x + 9 = (x + 3)2
Perfect Square Trinomial, middle term negative factors to Square of a Difference. x2 - 8x + 16 = (x - 4)2
When the lead coefficient = 1
When the sign of the constant term is positive (+): x2 + 5x + 6
find the factors of the constant term (+ 6) that add to the middle coefficient (+
5).
write the factors as the second term of two binomials with the variable as the first
term: (x + 2)(x + 3) then
Check by multiplying.
When the sign of the constant term is negative (-): x2 + 5x - 6
find the factors of the constant term (- 6) that subtract to the middle coefficient
(+ 5). The larger of the two factors of 6 will have the same sign as the 5!!
write the factors as the second term of two binomials with the variable as the first
term: (x - 1)(x + 6) then
Check by multiplying.
When the lead coefficient does NOT equal 1.
Our goal is to write the quadratic as a four term polynomial so that we can use the
Distributive Law to factor by Grouping. The quadratic expression in our example is
in the form of ax2 + bx + c 4x2 + 17x - 15 In our example, a = 4, b = 17, and c = - 15.
Multiply a times c: 4 * - 15 = - 60
Find the factors of ac that combine to equal b: +20 and - 3 multiply to - 60 and add to + 17
Replace bx with using the factors as coefficients: 4x2 - 3x + 20x - 15
Group the terms two by two with a plus sign in between: (4x2 - 3x) + (20x - 15)
Use the Distributive Law to factor out the GCF from each binomial: x(4x - 3) + 5(4x - 3)
Use the Distributive Law to factor out the GCF from binomial: x(4x - 3) + 5(4x - 3) becomes (4x - 3)(x + 5)
Check by multiplying.
Another example: Factor: 6x2 - 7x - 20 a = 6, c = - 20; ac = -120 8 * -15 = -120; 8 - 15 = -7 6x2 - 15x + 8x - 20 Group and (6x2 - 15x) + (8x - 20) factor with DL 3x(2x - 5) + 4(2x - 5) factor with DL 3x + 4)(2x - 5) Check by multiplying.